Re: [petsc-dev] MatMatMult gives different results
Alexander, I'm curious about why do you need parallel C=A^T*B? How large your matrices are? In petsc-dev, we have MatTransposeMatMult() for mpiaij and mpiaij, but not mpiaij and mpidense. We may add support of MatTransposeMatMult_MPIAIJ_MPIDense() if there is such need. Hong On Tue, Feb 7, 2012 at 1:18 PM, [email protected] < [email protected]> wrote:
Hong,
Thanks for explanation. I will try this tomorrow. Good to have this stuff in the help now.
And sorry for misleading you initially.
Regards, Alexander
----- Reply message ----- From: "Hong Zhang" <[email protected]> To: "For users of the development version of PETSc" <[email protected]
Subject: [petsc-dev] MatMatMult gives different results Date: Tue, Feb 7, 2012 19:09
Alexander :
There is something I didn't get yet, I hope you could clarify it.
So, when I use flag MAT_INITIAL_MATRIX in test program it works fine.
Good to know :-)
If I put this flag in my original program I get dozens of exceptions like: [42]PETSC ERROR: Argument out of range! [42]PETSC ERROR: New nonzero at (1336,153341) caused a malloc!
You cannot do MatCreateMPIAIJ() MatTranspose(A,MAT_INITIAL_MATRIX,&AT);
MatCreateMPIAIJ() creates AT and preallocates approximate nonzeros, which does not match exactly the nonzeros in MatTranspose(A,MAT_INITIAL_MATRIX,&AT); MatTranspose(A,MAT_INITIAL_MATRIX,&AT) creates matrix AT and sets correct nonzero pattern and values in AT. MatTranspose() only takes in "MAT_INITIAL_MATRIX" - for a new AT, and "MAT_REUSE_MATRIX" when AT is created with MatTranspose(A,MAT_INITIAL_MATRIX,&AT) and reuse for updating its values (not nonzero patten).
I'm updating petsc help menu on MatTranspose(). Thanks for the report.
Hong
I changed this flag to MAT_REUSE_MATRIX and exceptions disappeared, but result is incorrect again (same as for MAT_IGNORE_MATRIX) I tried test program with MAT_REUSE_MATRIX and it also gives different matrix product.
Since there is no description of MatReuse structure for MatTranspose it's a bit confusing what to expect from it.
Do you mean 'Cm = A'*B;'? 'Cm = A.'*B;' gives component-wise matrix product, not matrix product.
.' operator means non-Hermitian transpose. That is what I get with MatTranspose (in contrast with MatHermitianTranspose) component-wise matrix product would be .*
You are correct.
Hong
Hong
C = PetscBinaryRead('C.dat','complex',true);
Matrix C is different depending on number of cores I use. My PETSc is: Using Petsc Development HG revision: 876c894d95f4fa6561d0a91310ca914592527960 HG Date: Tue Jan 10 19:27:14 2012 +0100
On 06.02.2012 17:13, Hong Zhang wrote:
MatMatMult() in petsc is not well-tested for complex - could be buggy. Can you send us the matrices A and B in petsc binary format for investigation?
Hong
On Mon, Feb 6, 2012 at 5:55 AM, Alexander Grayver < [email protected]> wrote:
Dear PETSc team,
I try to use: call MatMatMult(A,B,MAT_INITIAL_MATRIX,PETSC_DEFAULT_DOUBLE_PRECISION,C,ierr);CHKERRQ(ierr)
Where both A and B are rectangular, but A is sparse and B is dense. Both are double complex and distributed. The product PETSc gives me contains some errors in some part of the matrix. I output A, B and C then computed product in matlab.
Attached you see figure plotted as: imagesc(log10(abs(C-Cm)))
Where Cm -- product computed in matlab.
The pattern and amplitude vary depending on the number of cores I use. This picture is obtained for 48 cores (I've tried 12, 64 cores as well).
Where should I look for possible explanation?
-- Regards, Alexander
-- Regards, Alexander
-- Regards, Alexander
-- Regards, Alexander
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Hong Zhang